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POST upload example:
post_upload.htm
===============
<html>
<body>
<form action=/cgi-bin/post_upload.cgi method=post enctype=multipart/form-data>
File to upload: <input type=file name=file1> <input type=submit>
</form>
post_upload.cgi
===============
#!/bin/sh
# POST upload format:
# -----------------------------29995809218093749221856446032^M
# Content-Disposition: form-data; name="file1"; filename="..."^M
# Content-Type: application/octet-stream^M
# ^M <--------- headers end with empty line
# file contents
# file contents
# file contents
# ^M <--------- extra empty line
# -----------------------------29995809218093749221856446032--^M
# Beware: bashism $'\r' is used to handle ^M
file=/tmp/$$-$RANDOM
# CGI output must start with at least empty line (or headers)
printf '\r\n'
IFS=$'\r'
read -r delim_line
IFS=''
delim_line="${delim_line}--"$'\r'
while read -r line; do
test "$line" = '' && break
test "$line" = $'\r' && break
done
# This will not work well for binary files: bash 3.2 is upset
# by reading NUL bytes and loses chunks of data.
# If you are not bothered by having junk appended to the uploaded file,
# consider using simple "cat >file" instead of the entire
# fragment below.
while read -r line; do
while test "$line" = $'\r'; do
read -r line
test "$line" = "$delim_line" && {
# Aha! Empty line + delimiter! All done
cat <<EOF
<html>
<body>
File upload has been accepted
EOF
exit 0
}
# Empty line + NOT delimiter. Save empty line,
# and go check next line
printf "%s\n" $'\r' >&3
done
# Not empty line - just save
printf "%s\n" "$line" >&3
done 3>"$file"
cat <<EOF
<html>
<body>
File upload was not terminated with '$delim_line' - ??!
EOF
|
