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authorDenys Vlasenko <vda.linux@googlemail.com>2017-04-10 11:47:48 +0200
committerDenys Vlasenko <vda.linux@googlemail.com>2017-04-10 11:47:48 +0200
commit4908c79a018cdea41d2899ebcef59831117a07cd (patch)
tree9597ce58bf51c045b135ba6f11e5723dc3f682ad
parentf428f1dc6cb9e9d3cfcfe3c555d44b6a7686cc88 (diff)
factor: better comments, slightl more clever conversion even->odd
function old new delta isqrt_odd 114 111 -3 Signed-off-by: Denys Vlasenko <vda.linux@googlemail.com>
-rw-r--r--coreutils/factor.c31
1 files changed, 26 insertions, 5 deletions
diff --git a/coreutils/factor.c b/coreutils/factor.c
index 5c4d124a8..aa2f63089 100644
--- a/coreutils/factor.c
+++ b/coreutils/factor.c
@@ -86,8 +86,9 @@ static inline half_t isqrt(wide_t N)
static NOINLINE half_t isqrt_odd(wide_t N)
{
half_t s = isqrt(N);
- if (s && !(s & 1)) /* even? */
- s--;
+ /* Subtract 1 from even s, odd s won't change: */
+ /* (doesnt work for zero, but we know that s != 0 here) */
+ s = (s - 1) | 1;
return s;
}
@@ -107,6 +108,16 @@ static NOINLINE void factorize(wide_t N)
N >>= 1;
}
+ /* The code needs to be optimized for the case where
+ * there are large prime factors. For example,
+ * this is not hard:
+ * 8262075252869367027 = 3 7 17 23 47 101 113 127 131 137 823
+ * (the largest factor to test is only ~sqrt(823) = 28)
+ * but this is:
+ * 18446744073709551601 = 53 348051774975651917
+ * the last factor requires testing up to
+ * 589959129 - about 100 million iterations.
+ */
max_factor = isqrt_odd(N);
count3 = 3;
count5 = 6;
@@ -130,18 +141,28 @@ static NOINLINE void factorize(wide_t N)
* 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47...
* ^ ^ ^ ^ ^ ^ ^ _ ^ ^ _ ^ ^ ^ ^
* (^ = primes, _ = would-be-primes-if-not-divisible-by-5)
+ * The numbers with space under them are excluded by sieve 3.
*/
count7--;
count5--;
count3--;
if (count3 && count5 && count7)
continue;
- if (count3 == 0)
+ /*
+ * "factor" is multiple of 3 33% of the time (count3 reached 0),
+ * else, multiple of 5 13% of the time,
+ * else, multiple of 7 7.6% of the time.
+ * Cumulatively, with 3,5,7 sieving we are here 54.3% of the time.
+ */
+ if (count3 == 0) {
count3 = 3;
- if (count5 == 0)
+ }
+ if (count5 == 0) {
count5 = 5;
- if (count7 == 0)
+ }
+ if (count7 == 0) {
count7 = 7;
+ }
goto next_factor;
}
end: